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2(6x^2-25)=25
We move all terms to the left:
2(6x^2-25)-(25)=0
We multiply parentheses
12x^2-50-25=0
We add all the numbers together, and all the variables
12x^2-75=0
a = 12; b = 0; c = -75;
Δ = b2-4ac
Δ = 02-4·12·(-75)
Δ = 3600
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{3600}=60$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-60}{2*12}=\frac{-60}{24} =-2+1/2 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+60}{2*12}=\frac{60}{24} =2+1/2 $
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